文件列表:

AR002 (0, 1999-12-09)
AR002\AR.C (9965, 1992-10-17)
AR002\AR.H (1974, 1990-08-15)
AR002\DECODE.C (1118, 1992-10-17)
AR002\ENCODE.C (8018, 1992-10-17)
AR002\HUF.C (7105, 1992-10-17)
AR002\IO.C (2365, 1992-10-17)
AR002\MAKEFILE (748, 1992-10-17)
AR002\MAKETBL.C (1525, 1992-10-17)
AR002\MAKETREE.C (2630, 1992-10-17)
ASH (0, 1999-12-09)
ASH\ARITH.C (7788, 1992-01-15)
ASH\ARITH.H (565, 1992-01-15)
ASH\COMP.H (1180, 1992-01-15)
ASH\COMPRESS.C (3478, 1992-01-15)
ASH\EXPAND.C (3628, 1992-01-15)
ASH\FILES.C (3875, 1992-01-15)
ASH\FILES.H (347, 1992-01-15)
ASH\MAKE.BAT (130, 1992-10-17)
ASH\MODEL.C (33986, 1992-01-15)
ASH\TEST.C (976, 1992-01-15)
COMP (0, 1999-12-09)
COMP\BITIO.C (5713, 1990-06-03)
COMP\BITIO.H (435, 1990-05-23)
COMP\CODER.C (6198, 1990-06-03)
COMP\CODER.H (1394, 1990-05-22)
COMP\COMP-1.C (4399, 1990-06-02)
COMP\COMP-2.C (7002, 1990-06-02)
COMP\EXPAND-1.C (4245, 1990-06-02)
COMP\EXPAND-2.C (4786, 1990-06-02)
COMP\MAKE.BAT (484, 1992-10-17)
COMP\MODEL-1.C (3193, 1990-06-02)
COMP\MODEL-1A.C (4562, 1990-05-25)
COMP\MODEL-2.C (27727, 1990-05-25)
COMP\MODEL-2A.C (6196, 1990-05-25)
COMP\MODEL.H (657, 1990-05-25)
COMP\READ.ME (2093, 1992-10-17)
FIN (0, 1999-12-09)
FIN\COMP2.ASM (3561, 1991-04-29)
... ...

1. The problem was caused by an overflow in the arithmetic coder due to long strings of repeated characters. This has been fixed. 2. The program now tests for repeated strings and bypasses the scan procedure. This has improved the performance significantly for the slowest files. 3. I have included all the source files and executables. Most of the changes are in MODEL.C. I have made some minor changes to some of the other routines, such as correcting spelling mistakes. 4. I have checked the underflow situation at end of file, and I am still convinced that my method works. The version of the arithetic coding algorithm published in the CACM presents random bits to the decoder at end of file, so that the final value output by the coder must include enough bits to allow the final symbol to be resolved no matter what follows. This means outputting the underflow bits plus two more to ensure the input value is bracketed by the high and low limits. I get around this problem by returning zeroes after the decoder detects end of file. Thank you for the chance to fix the problems. Charles.

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