说明：  设在内存区域中有数组X和Y。X数组有X1，X2，…，X10；Y数组有Y1，Y2，…，Y10，编程序实现下面的计算： Z1=X1－Y1，Z2=X2＋Y2，Z3=X3－Y3，Z4=X4＋Y4，Z5=X5＋Y5，Z6=X6－Y6，Z7=X7－Y7，Z8=X8＋Y8，Z9=X9－Y9，Z10=X10＋Y10。计算结果Z存放在数组Z中。 为了便于检查结果，设数组X的内容为db 22,11,22,11,11,22,22,11,22,11,0,0,0,0,0,0存放于ds：0的内存中，为了便于计算，把数组X中的数补足16个；数组Y存放于ds：16开始的16个内存中，内容为11,88,11,88,88,11,11,88,11,88,0,0,0,0,0,0，而数组Z存放于ds：32的内存空间中，且数组值初始化为0。 数组X、Y、Z都是连续存放的！
(Memory regions are located in an array of X and Y. X arrays are X1, X2, ..., X10 Y array with Y1, Y2, ..., Y10, programmed to achieve the following calculation: Z1 = X1-Y1, Z2 = X2+ Y2, Z3 = X3-Y3, Z4 = X4+ Y4, Z5 = X5+ Y5, Z6 = X6-Y6, Z7 = X7-Y7, Z8 = X8+ Y8, Z9 = X9-Y9, Z10 = X10+ Y10. The results stored in an array Z in Z. In order to facilitate the inspection results, set the contents of the array X as db 22,11,22,11,11,22,22,11,22,11,0,0,0,0,0,0 stored in ds: 0 Memory , in order to facilitate the calculation, the number of array X in the complement of 16 array Y stored in the ds: 16 of 16 starting in memory, says 11,88,11,88,88,11,11,88,11, 88,0,0,0,0,0,0, and stored in the array Z ds: 32 of the memory space, and the array value is initialized to 0. Array X, Y, Z are continuous storage!)