Newton.rar_newton_newton迭代法

<html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8"> <meta name="generator" content="pdf2htmlEX"> <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"> <link rel="stylesheet" href="https://static.pudn.com/base/css/base.min.css"> <link rel="stylesheet" href="https://static.pudn.com/base/css/fancy.min.css"> <link rel="stylesheet" href="https://static.pudn.com/prod/directory_preview_static/626774b64c65f412596cd364/raw.css"> <script src="https://static.pudn.com/base/js/compatibility.min.js"></script> <script src="https://static.pudn.com/base/js/pdf2htmlEX.min.js"></script> <script> try{ pdf2htmlEX.defaultViewer = new pdf2htmlEX.Viewer({}); }catch(e){} </script> <title></title> </head> <body> <div id="sidebar" style="display: none"> <div id="outline"> </div> </div> <div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://static.pudn.com/prod/directory_preview_static/626774b64c65f412596cd364/bg1.jpg"><div class="c x0 y1 w2 h2"><div class="t m0 x1 h3 y2 ff1 fs0 fc0 sc0 ls0 ws0">问题描述：</div><div class="t m0 x1 h3 y3 ff2 fs0 fc0 sc0 ls0 ws0">y=54*x.^6+45*x.^5-102*x.^4-69*x.^3+35*x.^2+16*x-4<span class="_ _0"></span><span class="ff1">（</span>matlab<span class="_ _1"> </span><span class="ff1">图像如图）</span></div><div class="t m0 x1 h3 y4 ff1 fs0 fc0 sc0 ls0 ws0">求此方程的零点，本文<span class="_ _1"> </span><span class="ff2">matlab<span class="_ _1"> </span></span>程序中利用<span class="ff2">(1)<span class="_ _2"> </span>Newton<span class="_ _1"> </span></span>迭代法求零点。</div><div class="t m0 x1 h3 y5 ff1 fs0 fc0 sc0 ls0 ws0">输出结果：</div><div class="t m0 x1 h4 y6 ff2 fs0 fc0 sc0 ls0 ws0">x_out =</div><div class="t m0 x1 h4 y7 ff2 fs0 fc0 sc0 ls0 ws0">-1.3813 -1.3813 -0.6667 -0.6667 0.2052 0.5000 1.1761 1.1761 </div><div class="t m0 x1 h4 y8 ff2 fs0 fc0 sc0 ls0 ws0">1.1761</div><div class="t m0 x1 h3 y9 ff1 fs0 fc0 sc0 ls0 ws0">所以零点为：</div><div class="t m0 x1 h4 ya ff2 fs0 fc0 sc0 ls0 ws0">x_1=-1.3813; x_2= -0.6667; x_3=0.2052;x_4=0.5000; x_5=1.1761</div></div></div><div class="pi" data-data='{"ctm":[1.611850,0.000000,0.000000,1.611850,0.000000,0.000000]}'></div></div> </body> </html>