• 木木山风
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  • matlab
    开发工具
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  • 2020-05-21 23:54
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在MatLab中,利用角谱理论,模拟了物体经过透镜成像的过程。 例子中 物体为读入的图像(五角星),在放大倍数为1、2、6倍的情况下分别模拟。
Ch3_lens_imaging_simulation.zip
  • Ch3_lens_imaging_simulation.mlx
    174.7KB
  • Ch3_result.png
    382.9KB
  • pentagram.bmp
    88.9KB
  • Ch3_lens_imaging_simulation.pdf
    171.4KB
内容介绍
<html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8"> <meta name="generator" content="pdf2htmlEX"> <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"> <link rel="stylesheet" href="https://static.pudn.com/base/css/base.min.css"> <link rel="stylesheet" href="https://static.pudn.com/base/css/fancy.min.css"> <link rel="stylesheet" href="https://static.pudn.com/prod/directory_preview_static/625399256caf596192a4119f/raw.css"> <script src="https://static.pudn.com/base/js/compatibility.min.js"></script> <script src="https://static.pudn.com/base/js/pdf2htmlEX.min.js"></script> <script> try{ pdf2htmlEX.defaultViewer = new pdf2htmlEX.Viewer({}); }catch(e){} </script> <title></title> </head> <body> <div id="sidebar" style="display: none"> <div id="outline"> </div> </div> <div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://static.pudn.com/prod/directory_preview_static/625399256caf596192a4119f/bg1.jpg"><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls0 ws0">&#20809;&#22330;&#36880;&#27425;&#20256;&#25773;</div><div class="t m0 x2 h3 y2 ff2 fs0 fc0 sc0 ls0 ws0">&#183;</div><div class="t m0 x3 h2 y1 ff1 fs0 fc0 sc0 ls0 ws0">&#25104;&#20687;</div><div class="t m0 x1 h4 y3 ff1 fs1 fc1 sc0 ls0 ws0">&#20809;&#36335;&#24773;&#20917;&#65306;</div><div class="t m0 x1 h5 y4 ff3 fs1 fc1 sc0 ls0 ws0"> U0 Ul1 Ul2 Ui</div><div class="t m0 x1 h5 y5 ff3 fs1 fc1 sc0 ls0 ws0">|Object| (lens) |Image|</div><div class="t m0 x1 h6 y6 ff2 fs2 fc2 sc0 ls0 ws0"> <span class="ff4">&lt;--Z_1--&gt; </span> <span class="ff4">&lt;---Z_2---&gt;</span></div><div class="t m0 x4 h7 y7 ff4 fs2 fc3 sc0 ls0 ws0">% </div><div class="t m0 x5 h8 y8 ff1 fs2 fc3 sc0 ls0 ws0">&#21333;&#20301;&#30342;&#20026;</div><div class="t m0 x6 h7 y7 ff4 fs2 fc3 sc0 ls0 ws0"> um</div><div class="t m0 x4 h7 y9 ff4 fs2 fc2 sc0 ls0 ws0">f = 100; <span class="fc3">% </span></div><div class="t m0 x7 h8 ya ff1 fs2 fc3 sc0 ls0 ws0">&#28966;&#36317;</div><div class="t m0 x4 h7 yb ff4 fs2 fc2 sc0 ls0 ws0">D = 420; <span class="fc3">% </span></div><div class="t m0 x7 h8 yc ff1 fs2 fc3 sc0 ls0 ws0">&#36879;&#38236;&#30452;&#24452;</div><div class="t m0 x4 h7 yd ff4 fs2 fc2 sc0 ls0 ws0">lambda = 0.633; <span class="fc3">% </span></div><div class="t m0 x7 h8 ye ff1 fs2 fc3 sc0 ls0 ws0">&#27874;&#38271;</div><div class="t m0 x4 h7 yf ff4 fs2 fc2 sc0 ls0 ws0">M = [1, 2, 6]; <span class="fc3">% </span></div><div class="t m0 x7 h8 y10 ff1 fs2 fc3 sc0 ls0 ws0">&#25918;&#22823;&#20493;&#25968;</div><div class="t m0 x4 h7 y11 ff4 fs2 fc2 sc0 ls0 ws0"> </div><div class="t m0 x4 h7 y12 ff4 fs2 fc3 sc0 ls0 ws0">% </div><div class="t m0 x5 h8 y13 ff1 fs2 fc3 sc0 ls0 ws0">&#30001;</div><div class="t m0 x8 h7 y12 ff4 fs2 fc3 sc0 ls0 ws0">M=z2/z1, 1/z1+1/z2=1/f </div><div class="t m0 x9 h8 y13 ff1 fs2 fc3 sc0 ls0 ws0">&#21487;&#27714;&#24471;</div><div class="t m0 xa h7 y12 ff4 fs2 fc3 sc0 ls0 ws0">z1, </div><div class="t m0 xb h8 y13 ff1 fs2 fc3 sc0 ls0 ws0">z2&#65307;</div><div class="t m0 x4 h7 y14 ff4 fs2 fc2 sc0 ls0 ws0">z1 = [2*f, 1.5*f, 7/6*f];</div><div class="t m0 x4 h7 y15 ff4 fs2 fc2 sc0 ls0 ws0">z2 = [2*f, 3*f, 7*f]; </div><div class="t m0 x1 h4 y16 ff1 fs1 fc1 sc0 ls0 ws0">&#35835;&#20837;&#22270;&#20687;</div><div class="t m0 x4 h7 y17 ff4 fs2 fc2 sc0 ls0 ws0">Object = imread(<span class="fc4">'pentagram.bmp'</span>);</div><div class="t m0 x4 h7 y18 ff4 fs2 fc2 sc0 ls0 ws0">imshow(Object);</div><div class="t m0 xc h9 y19 ff5 fs2 fc2 sc0 ls0 ws0">1</div></div><div class="pi" data-data='{"ctm":[1.568627,0.000000,0.000000,1.568627,0.000000,0.000000]}'></div></div> </body> </html>
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