基于二次多项式响应面的机械可靠性分析算例.zip

• Blessedhy
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• matlab
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• 2022-01-22 09:22
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• D2.2.mat
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• RSM2.m
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clc clear all %% data input load('D2.2.mat') y1 = St; y2 = De; x1 = T; x2 = L; x3 = M; x4 = F; %% do not include cross terms for deformation simulation X1=[ones(size(y1)) x1 x2 x3 x4 x1.^2 x2.^2 x3.^2 x4.^2 ]; [b1,bint1,r1,rint1,stats1] = regress(y2,X1); Yp=b1(1)+b1(2)*x1 + b1(3)*x2 + b1(4)*x3 + b1(5)*x4 + b1(6)*x1.^2 +... b1(7)*x2.^2 + b1(8)*x3.^2 +b1(9)*x4.^2; %% including cross terms for stress simulation % X1=[ones(size(y1)) x1 x2 x3 x4 x1.*x2 x1.*x3 x1.*x4 x2.*x3... % x2.*x4 x3.*x4 ]; % [b1,bint1,r1,rint1,stats1] = regress(y1,X1); % % Yp=b1(1)+b1(2)*x1 + b1(3)*x2 + b1(4)*x3 + b1(5)*x4 + b1(6)*x1.*x2 +... % b1(7)*x1.*x3 + b1(8)*x1.*x4 + b1(9)*x2.*x3 + b1(10)*x2.*x4 + b1(11)*x3.*x4; %% visualization subplot(1,2,1) plot(y2,'-b*','MarkerSize',8) hold on plot(Yp,'-bo','MarkerSize',8) legend('Real output','Estimate output') %% reliability carculation based on monte carlo simulation number = 100000;% 抽样次数 TMC = 0.03 + 0.0004*randn(number,1); x1 = TMC; LMC = 0.3 + 0.006*randn(number,1); x2 = LMC; MMC = 12391 + 247.82*randn(number,1); x3 = MMC; FMC = 43341 + 866.82*randn(number,1); x4 = FMC; YMCp=b1(1)+b1(2)*x1 + b1(3)*x2 + b1(4)*x3 + b1(5)*x4 + b1(6)*x1.^2 +... b1(7)*x2.^2 + b1(8)*x3.^2 +b1(9)*x4.^2;%deformation prediction % YMCp=b1(1)+b1(2)*x1 + b1(3)*x2 + b1(4)*x3 + b1(5)*x4 + b1(6)*x1.*x2 +... % b1(7)*x1.*x3 + b1(8)*x1.*x4 + b1(9)*x2.*x3 + b1(10)*x2.*x4 + b1(11)*x3.*x4;%stress prediction subplot(1,2,2) histfit(YMCp,75) Ya = 270e6;%allowable value for stress Yaa = 9e-4;%allowable value for deformation R = sum(YMCp<Yaa)/number

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