递推算法,递归讲解,全面啊

  • F6_808417
    了解作者
  • 221.7KB
    文件大小
  • rar
    文件格式
  • 0
    收藏次数
  • VIP专享
    资源类型
  • 0
    下载次数
  • 2022-04-22 01:03
    上传日期
计算机课件,全面讲解递推的算法,很不错的的的的的!
(lecture_03)递推求解.rar
  • (lecture_03)递推求解.ppt
    452KB
内容介绍
<html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8"> <meta name="generator" content="pdf2htmlEX"> <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"> <link rel="stylesheet" href="https://static.pudn.com/base/css/base.min.css"> <link rel="stylesheet" href="https://static.pudn.com/base/css/fancy.min.css"> <link rel="stylesheet" href="https://static.pudn.com/prod/directory_preview_static/626c68be7ae5df2aa7352ba1/raw.css"> <script src="https://static.pudn.com/base/js/compatibility.min.js"></script> <script src="https://static.pudn.com/base/js/pdf2htmlEX.min.js"></script> <script> try{ pdf2htmlEX.defaultViewer = new pdf2htmlEX.Viewer({}); }catch(e){} </script> <title></title> </head> <body> <div id="sidebar" style="display: none"> <div id="outline"> </div> </div> <div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://static.pudn.com/prod/directory_preview_static/626c68be7ae5df2aa7352ba1/bg1.jpg"><div class="c x0 y1 w2 h2"><div class="t m0 x1 h3 y2 ff1 fs0 fc0 sc0 ls0 ws0">ACM<span class="_ _0"> </span>&#31243;&#24207;&#35774;&#35745;</div><div class="t m0 x2 h4 y3 ff1 fs1 fc1 sc1 ls0 ws0">&#26477;&#24030;&#30005;&#23376;&#31185;&#25216;&#22823;&#23398; &#21016;&#26149;&#33521;</div><div class="t m0 x3 h4 y4 ff1 fs1 fc1 sc1 ls0 ws0">acm@hdu.<span class="_ _1"></span>edu.cn</div></div></div><div class="pi" data-data='{"ctm":[1.333333,0.000000,0.000000,1.333333,0.000000,0.000000]}'></div></div> </body> </html>
评论